Matematika Sekolah Menengah Pertama 2 per 3-√8dibantu ya kak​

Mafalda Crooks – March 08, 2023

2 per 3-√8
dibantu ya kak​

Jawaban:

[tex] \frac{2}{3 - \sqrt{8} } [/tex]

[tex] = \frac{2}{3 - 2 \sqrt{2} } [/tex]

[tex] = \frac{2}{3 - 2 \sqrt{2} } \times \frac{3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} } [/tex]

[tex] = \frac{2(3 + 2 \sqrt{2}) }{(3 - 2 \sqrt{2} ) \times (3 + 2 \sqrt{2}) } [/tex]

[tex] = \frac{2(3 + 2 \sqrt{2}) }{9 - 4 \times 2} [/tex]

[tex] = \frac{2(3 + 2 \sqrt{2}) }{9 -8} [/tex]

[tex] = \frac{2(3 + 2 \sqrt{2}) }{1} [/tex]

[tex] = 2(3 + 2 \sqrt{2})[/tex]

[tex] = 6 + 4 \sqrt{2} [/tex]

Jawab :

[tex]=\bf6+4\sqrt2[/tex]

Penjelasan :

[tex]\displaystyle\frac{2}{3-\sqrt{8}}\\\\=\frac{2(3+\sqrt{8})}{(3-\sqrt{8})(3+\sqrt{8})}\\\\=\frac{2(3)+2\sqrt{8}}{3^2-(\sqrt{8})^2}\\\\=\frac{6+2\sqrt{4}\sqrt2}{9-8}\\\\=\frac{6+2(2)\sqrt2}{\not1}\\\\=\bf6+4\sqrt2[/tex]

(xcvi)

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